Question

The correct relationship of mobility \( \mu \) of charge carrier with drift velocity \( v_d \) and electric field \( E \), is:

• A. \( \mu = \frac{v_d}{E} \)
• B. \( \mu = \frac{E}{v_d} \)
• C. \( \mu = E v_d \)
• D. \( \mu = E + v_d \)

Hint:

The mobility of charge carriers is the ratio of their drift velocity to the applied electric field, i.e., \( \mu = \frac{v_d}{E} \).

Answer 1

The Correct Option is A

The mobility \( \mu \) of a charge carrier is defined as the ratio of its drift velocity \( v_d \) to the applied electric field \( E \). Mathematically, this is expressed as:
\[ \mu = \frac{v_d}{E} \] Where: - \( v_d \) is the drift velocity of the charge carrier, - \( E \) is the electric field applied.
Mobility is a measure of how quickly a charge carrier can move through a medium under the influence of an electric field. Therefore, the correct relationship is \( \mu = \frac{v_d}{E} \), which makes option (A) the correct answer.
Hence, the correct answer is option (A) \( \mu = \frac{v_d}{E} \).