The correct match between item 'I' and item 'II' is :
Item 'I' (compound) Item 'II' (reagent) (A) Lysine (P) 1-naphthol (B) Furfural (Q) ninhydrin (C) Benzylalcohol (R) KMnO4 (D) Styrene (S) Ceric ammonium nitrate
| Item 'I' (compound) | Item 'II' (reagent) |
| (A) Lysine | (P) 1-naphthol |
| (B) Furfural | (Q) ninhydrin |
| (C) Benzylalcohol | (R) KMnO4 |
| (D) Styrene | (S) Ceric ammonium nitrate |
Show Hint
- (A) → (Q); (B) → (R); (C) → (S); (D) → (P)
- (A) → (Q); (B) → (P); (C) → (S); (D) → (R)
- (A) → (R); (B) → (P); (C) → (Q); (D) → (S)
- (A) → (Q); (B) → (P); (C) → (R); (D) → (S)
The Correct Option is B
Solution and Explanation
(B) Furfural, an aldehyde from pentoses, condenses with 1-naphthol (alpha-naphthol) in conc. H2SO4 to give a purple ring, as in the Molisch test: B to P.
(C) Benzyl alcohol (an alcohol) gives a red/orange complex with ceric ammonium nitrate (CAN test for alcohols): C to S.
(D) Styrene has a C=C which decolourises alkaline KMnO4 (Baeyer's test): D to R.
So A-Q, B-P, C-S, D-R.
Answer: (2) (A) \u2192 (Q); (B) \u2192 (P); (C) \u2192 (S); (D) \u2192 (R)
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