To solve this problem, we need to identify the chemical formula of fluoroapatite, which is formed when fluoride ions (F-) convert hydroxyapatite into a harder substance. The chemical reaction replaces the hydroxyl (OH)- groups in hydroxyapatite with fluoride ions to form fluoroapatite.
Hydroxyapatite, the mineral component of tooth enamel, has the formula:
\(Ca_5(PO_4)_3(OH)\)
When fluoride ions are introduced, they replace the hydroxide ions, creating fluoroapatite:
\(Ca_5(PO_4)_3F\)
However, the formula for fluoroapatite often considered in bulk compositions is:
\(3Ca_3(PO_4)_2.CaF_2\)
Let's evaluate the given options to find the correct formula for fluoroapatite:
After analyzing the options, the correct formula for fluoroapatite is:
\([3(Ca_3(PO_4)_2).CaF_2]\)
Hence, the correct answer is the first option.
Explanation:
- Hydroxyapatite, [Ca5(PO4)3(OH)], is present in tooth enamel.
- When fluoride ions (F−) are introduced, they replace the hydroxide ions (OH−), forming fluoroapatite:
Ca5(PO4)3(OH) + F− → Ca5(PO4)3F.
- Fluoroapatite has the molecular formula [3(Ca3(PO4)2·CaF2)], which is harder and more resistant to decay.
Final Answer: Option (1).
MX is a sparingly soluble salt that follows the given solubility equilibrium at 298 K.
MX(s) $\rightleftharpoons M^{+(aq) }+ X^{-}(aq)$; $K_{sp} = 10^{-10}$
If the standard reduction potential for $M^{+}(aq) + e^{-} \rightarrow M(s)$ is $(E^{\circ}_{M^{+}/M}) = 0.79$ V, then the value of the standard reduction potential for the metal/metal insoluble salt electrode $E^{\circ}_{X^{-}/MX(s)/M}$ is ____________ mV. (nearest integer)
[Given : $\frac{2.303 RT}{F} = 0.059$ V]
An infinitely long straight wire carrying current $I$ is bent in a planar shape as shown in the diagram. The radius of the circular part is $r$. The magnetic field at the centre $O$ of the circular loop is :
