Question

The correct match between Item-I and Item-II is :

Item-I (drug)	Item-II (test)
A. Chloroxylenol	P. Carbylamine test
B. Norethindrone	Q. Sodium hydrogen carbonet test
C. Sulphapyridine	R. Ferric chloride test
D. Penicillin	S. Bayer's test

• A. A \(\rightarrow\) R; B \(\rightarrow\) P; C \(\rightarrow\) S; D \(\rightarrow\) Q
• B. A \(\rightarrow\) Q; B \(\rightarrow\) S; C \(\rightarrow\) P; D \(\rightarrow\) R
• C. A \(\rightarrow\) R; B \(\rightarrow\) S; C \(\rightarrow\) P; D \(\rightarrow\) Q
• D. A \(\rightarrow\) Q; B \(\rightarrow\) P; C \(\rightarrow\) S; D \(\rightarrow\) R

Hint:

Identify the functional group in each drug: phenolic OH, alkyne, aromatic primary amine, carboxylic acid.

Answer 1

The Correct Option is C

Match each drug with the functional group that gives the test:
A. Chloroxylenol is a chlorinated phenol (antiseptic): phenolic -OH gives a coloured complex with neutral \(\mathrm{FeCl_3}\), so A \(\rightarrow\) R.
B. Norethindrone contains an ethynyl (C\(\equiv\)CH) group and a C=C: unsaturation decolourises Baeyer's reagent (alkaline \(\mathrm{KMnO_4}\)), so B \(\rightarrow\) S.
C. Sulphapyridine (sulpha drug) has a free aromatic primary amino group (-\(\mathrm{NH_2}\)): it gives the carbylamine (isocyanide) test, so C \(\rightarrow\) P.
D. Penicillin has a free -COOH group: it liberates \(\mathrm{CO_2}\) with \(\mathrm{NaHCO_3}\), so D \(\rightarrow\) Q.
Hence A-R, B-S, C-P, D-Q.
Answer: (3) A \(\rightarrow\) R; B \(\rightarrow\) S; C \(\rightarrow\) P; D \(\rightarrow\) Q