The compound A on treatment with Na gives B, and with PCl5 gives C. B and C react together to give diethyl ether. A, B and C are in the order
- C2H5OH, C2H6 , C2H5Cl
- C2H5Cl, C2H6 , C2H5OH
- C2H5OH, C2H5Cl, C2H5ONa
- C2H5OH, C2H5ONa, C2H5Cl
The Correct Option is D
Solution and Explanation
To determine the correct option for the compounds A, B, and C, we need to analyze the chemical reactions described:
- Compound A reacts with Na to give B.
- Compound A reacts with PCl5 to give C.
- Compounds B and C react together to form diethyl ether.
Let's decipher each part systematically:
-
Reaction of A with Na:
This reaction usually involves alcohols, where the alcohol reacts with sodium to form sodium alkoxide and hydrogen gas. For example, ethanol (C2H5OH) reacts with sodium (Na) to form sodium ethoxide (C2H5ONa) and hydrogen (H2) gas:
\[ \text{C}_2\text{H}_5\text{OH} + \text{Na} \rightarrow \text{C}_2\text{H}_5\text{ONa} + \frac{1}{2}\text{H}_2 \]Thus, B is C2H5ONa.
-
Reaction of A with PCl5:
Alcohols react with phosphorus pentachloride (PCl5) to form alkyl chlorides. For example, ethanol (C2H5OH) reacts with PCl5 to form ethyl chloride (C2H5Cl):
\[ \text{C}_2\text{H}_5\text{OH} + \text{PCl}_5 \rightarrow \text{C}_2\text{H}_5\text{Cl} + \text{POCl}_3 + \text{HCl} \]Thus, C is C2H5Cl.
-
Reaction of B and C to form diethyl ether:
Diethyl ether (C2H5OC2H5) can be formed via the Williamson ether synthesis, which involves the reaction of an alkoxide ion (B: C2H5ONa) with an alkyl halide (C: C2H5Cl):
\[ \text{C}_2\text{H}_5\text{ONa} + \text{C}_2\text{H}_5\text{Cl} \rightarrow \text{C}_2\text{H}_5\text{OC}_2\text{H}_5 + \text{NaCl} \]
Based on these reactions, the correct order of A, B, and C is:
A = C2H5OH; B = C2H5ONa; C = C2H5Cl.
Correct Answer: C2H5OH, C2H5ONa, C2H5Cl
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