To solve the problem, we need to determine the transmissivity of each aquifer and then compare them. Transmissivity (\(T\)) is calculated as the product of the coefficient of permeability (\(K\)) and the saturated thickness (\(d\)) of the aquifer. Thus, the formula is:
\(T = K \times d\)
Calculate the transmissivity for Aquifer 1:
\(T_1 = 60 \, \text{m/day} \times 30 \, \text{m} = 1800 \, \text{m}^2/\text{day}\)
Next, calculate the transmissivity for Aquifer 2:
\(T_2 = 40 \, \text{m/day} \times 15 \, \text{m} = 600 \, \text{m}^2/\text{day}\)
Now, determine how many times larger the transmissivity of aquifer 1 is compared to aquifer 2 by dividing \(T_1\) by \(T_2\):
\(\frac{T_1}{T_2} = \frac{1800}{600} = 3\)
The result is 3, which indicates that the transmissivity of aquifer 1 is 3 times that of aquifer 2.