We are given the expansion:
\[
(1 + 3x + 3x^2 + x^3)^{20}
\]
Notice that:
\[
1 + 3x + 3x^2 + x^3 = (1 + x)^3
\]
Hence, the given expression simplifies as:
\[
[(1 + x)^3]^{20} = (1 + x)^{60}
\]
Now, we are to find the coefficient of \( x^{20} \) in the expansion of \( (1 + x)^{60} \).
From the binomial expansion:
\[
(1 + x)^{60} = \sum_{k=0}^{60} \binom{60}{k} x^k
\]
So, the coefficient of \( x^{20} \) is:
\[
\binom{60}{20}
\]
Using the identity:
\[
\binom{n}{r} = \binom{n}{n - r}
\Rightarrow \binom{60}{20} = \binom{60}{40}
\]
Thus, the required coefficient is \( \binom{60}{40} \).