The coefficient of variation of Poisson distribution with mean 9 is
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For any Poisson distribution, the coefficient of variation is simplified as $\text{CV} = \frac{\sqrt{\lambda}}{\lambda} \times 100 = \frac{100}{\sqrt{\lambda}}$. With $\lambda = 9$, $\text{CV} = \frac{100}{3}$.
Step 1: Understanding the Concept:
The Coefficient of Variation (CV) is a relative measure of dispersion, expressed as a percentage of the mean. Key Formula or Approach:
The formula for the Coefficient of Variation is:
\[ \text{CV} = \frac{\sigma}{\mu} \times 100 \]
where $\sigma$ is the standard deviation and $\mu$ is the mean. Step 2: Detailed Explanation:
For a Poisson distribution with parameter $\lambda$:
\[ \text{Mean} (\mu) = \lambda \]
\[ \text{Variance} (\sigma^2) = \lambda \implies \text{Standard Deviation} (\sigma) = \sqrt{\lambda} \]
Given that the mean of the Poisson distribution is $\lambda = 9$:
\[ \mu = 9 \]
\[ \sigma = \sqrt{9} = 3 \]
Substitute these values into the CV formula:
\[ \text{CV} = \frac{3}{9} \times 100 = \frac{1}{3} \times 100 = 100 \times \left(\frac{1}{3}\right) \]
This calculation yields a coefficient of variation equal to $33.33%$. Step 3: Final Answer:
The coefficient of variation is $100 \times (1/3)$.