Concept:
Two years will have the same calendar if:
• The starting day of the year is same.
• Both years are either leap years or non-leap years.
Since 2025 is not a leap year, we need another non-leap year with the same day pattern.
Step 1: Check whether 2025 is leap year or not.
A leap year is divisible by 4.
\[
2025 \div 4 \neq \text{integer}
\]
So,
\[
2025 \text{ is a non-leap year}
\]
Step 2: Count odd days year by year.
For non-leap year:
\[
1 \text{ odd day}
\]
For leap year:
\[
2 \text{ odd days}
\]
Now:
\[
2026 = 1
\]
\[
2027 = 1
\]
\[
2028 = 2 \; (\text{leap year})
\]
\[
2029 = 1
\]
\[
2030 = 1
\]
Total odd days:
\[
1+1+2+1+1=6
\]
Step 3: Check next year.
For 2031:
Add one more odd day:
\[
6+1=7
\]
\[
7 \equiv 0 \pmod{7}
\]
This means the calendar repeats.
Step 4: Final conclusion.
Hence, the year having the same calendar as 2025 is:
\[
\boxed{2031}
\]