Question:
The breakdown voltage of a zener diode is \(10\,V\). It is used in a voltage regulator circuit shown in figure. Current through zener diode is
center
The breakdown voltage of a zener diode is \(10\,V\). It is used in a voltage regulator circuit shown in figure. Current through zener diode is
center
Show Hint
In zener regulator:
\[
I_{\text{series}}=I_Z+I_L
\]
Always calculate total current first using series resistor.
Updated On: Jun 17, 2026
- \(20\,mA\)
- \(30\,mA\)
- \(32\,mA\)
- \(12\,mA\)
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The Correct Option is B
Solution and Explanation
Step 1: Understand zener regulation.
Since zener voltage is:
\[
V_Z=10V
\]
Voltage across load resistance:
\[
V_L=10V
\]
Step 2: Calculate current through series resistor. Supply voltage: \[ 18V \] Voltage drop across \(200\Omega\): \[ 18-10=8V \] Therefore: \[ I=\frac{8}{200}=0.04A=40mA \]
Step 3: Calculate load current. Load resistance: \[ 1k\Omega \] Thus: \[ I_L=\frac{10}{1000}=10mA \]
Step 4: Find zener current. \[ I_Z=40-10 \] \[ I_Z=30mA \] Hence: \[ \boxed{30mA} \]
Step 2: Calculate current through series resistor. Supply voltage: \[ 18V \] Voltage drop across \(200\Omega\): \[ 18-10=8V \] Therefore: \[ I=\frac{8}{200}=0.04A=40mA \]
Step 3: Calculate load current. Load resistance: \[ 1k\Omega \] Thus: \[ I_L=\frac{10}{1000}=10mA \]
Step 4: Find zener current. \[ I_Z=40-10 \] \[ I_Z=30mA \] Hence: \[ \boxed{30mA} \]
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