Question:

The Boolean expression \((p \wedge \sim q) \Rightarrow (q \vee \sim p)\) is equivalent to :

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Use \(A \Rightarrow B \equiv \sim A \vee B\) and De Morgan's laws, then simplify.
Updated On: Nov 4, 2026
  • \(q \Rightarrow p\)
  • \(p \Rightarrow q\)
  • \(\sim q \Rightarrow p\)
  • \(p \Rightarrow \sim q\)
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The Correct Option is B

Solution and Explanation

Use \(A \Rightarrow B \equiv \sim A \vee B\).
\((p \wedge \sim q) \Rightarrow (q \vee \sim p) \equiv \sim(p \wedge \sim q) \vee (q \vee \sim p)\).
By De Morgan's law, \(\sim(p \wedge \sim q) = \sim p \vee q\).
So the expression is \((\sim p \vee q) \vee (q \vee \sim p) = \sim p \vee q\).
But \(\sim p \vee q \equiv p \Rightarrow q\).
Answer: (2) \(p \Rightarrow q\)
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