Question:

The Boolean expression \(\overline{(A+B+C)}\) is equal to

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De Morgan's laws: \[ \boxed{ \overline{A+B}=\bar{A}\,\bar{B} } \] \[ \boxed{ \overline{AB}=\bar{A}+\bar{B} } \]
Updated On: Jul 14, 2026
  • \(\bar{A}+\bar{B}+\bar{C}\)
  • \(A(B+C)\)
  • \((A+B)C\)
  • \(\bar{A}\,\bar{B}\,\bar{C}\)
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The Correct Option is D

Solution and Explanation

Step 1: Apply De Morgan's theorem. According to De Morgan's law, \[ \overline{X+Y+Z} = \bar{X}\,\bar{Y}\,\bar{Z}. \]

Step 2:
Substitute the variables. Therefore, \[ \overline{(A+B+C)} = \bar{A}\,\bar{B}\,\bar{C}. \] Hence, \[ \boxed{\bar{A}\,\bar{B}\,\bar{C}} \] Therefore, \[ \boxed{(D)} \] is the correct answer.
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