Question:
The bandwidth of a tuned circuit is
The bandwidth of a tuned circuit is
Show Hint
Bandwidth = difference of cutoff frequencies.
Updated On: Jul 2, 2026
- \(3\,MHz\)
- \(7\,MHz\)
- \(5\,MHz\)
- \(4\,MHz\)
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The Correct Option is B
Solution and Explanation
Concept:
Bandwidth:
\[
BW = f_2 - f_1
\]
Step 1: Identify cutoff frequencies From given data: \(f_2\) and \(f_1\).
Step 2: Substitute values \[ BW = 7\,MHz \]
Step 3: Interpretation Bandwidth defines frequency range.
Step 4: Physical meaning Higher BW → wider signal range.
Step 5: Conclusion \[ \boxed{7\,MHz} \]
Final Answer: \[ \boxed{(B)} \]
Step 1: Identify cutoff frequencies From given data: \(f_2\) and \(f_1\).
Step 2: Substitute values \[ BW = 7\,MHz \]
Step 3: Interpretation Bandwidth defines frequency range.
Step 4: Physical meaning Higher BW → wider signal range.
Step 5: Conclusion \[ \boxed{7\,MHz} \]
Final Answer: \[ \boxed{(B)} \]
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