Question:
The average power generated by a 90 kg mountain climber who climbs a summit of height 600 m in 90 minutes is ($g=10~ms^{-2}$)
The average power generated by a 90 kg mountain climber who climbs a summit of height 600 m in 90 minutes is ($g=10~ms^{-2}$)
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Always ensure time is in seconds (SI units) before calculating Power in Watts.
Updated On: Jul 4, 2026
- 100 W
- 25 W
- 200 W
- 50 W
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The Correct Option is A
Solution and Explanation
Step 1: Concept
Power ($P$) is the rate of doing work, $P = W/t$. For climbing, $W = mgh$.
Step 2: Meaning
Given $m = 90$ kg, $h = 600$ m, and $t = 90$ minutes. Convert time to seconds: $t = 90 \times 60 = 5400$ s.
Step 3: Analysis
$W = 90 \times 10 \times 600 = 540,000$ J.
Step 4: Conclusion
$P = 540,000 / 5400 = 100$ W. Final Answer: (A)
Power ($P$) is the rate of doing work, $P = W/t$. For climbing, $W = mgh$.
Step 2: Meaning
Given $m = 90$ kg, $h = 600$ m, and $t = 90$ minutes. Convert time to seconds: $t = 90 \times 60 = 5400$ s.
Step 3: Analysis
$W = 90 \times 10 \times 600 = 540,000$ J.
Step 4: Conclusion
$P = 540,000 / 5400 = 100$ W. Final Answer: (A)
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