Question

The average kinetic energy of an ideal gas molecule in SI units at 25°C will be:

• A. \(6.17\times10^{-21}\,\text{J}\)
• B. \(6.17\times10^{-20}\,\text{J}\)
• C. \(6.7\times10^{-20}\,\text{J}\)
• D. 7.16×10⁻20J

Hint:

Average kinetic energy depends only on absolute temperature.

Answer 1

The Correct Option is A

Step 1: Average kinetic energy: overlineEk=(3)/(2)kT
Step 2: At T=298K: overlineEk=(3)/(2)(1.38×10⁻23)(298) ≈ 6.17×10⁻21J