Question:

The atomic numbers of the elements X, Y, Z are $a, a+1, a+2$ respectively. Z is an alkali metal. The nature of bonding in the compound formed by X and Z is

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The key to this problem is recognizing the sequence of element groups. A noble gas is always followed by an alkali metal in the next period. The combination of an alkali metal (Group 1) and a halogen (Group 17) will always result in an ionic bond due to the large difference in electronegativity.
Updated On: Mar 30, 2026
  • Covalent
  • Metallic
  • Ionic
  • Coordinate covalent
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The Correct Option is C

Solution and Explanation

Step 1: Determine the positions of X, Y, and Z in the periodic table.
The atomic numbers are consecutive: $Z_{\text{X}}=a$, $Z_{\text{Y}}=a+1$, $Z_{\text{Z}}=a+2$. This means X, Y, and Z are elements that appear one after the other in the periodic table (or X and Y are in one period and Z is in the next).
The element Z ($Z_{\text{Z}}=a+2$) is an alkali metal. Alkali metals belong to Group 1 (IA).

Step 2: Determine the group of X and Y.
If Z is in Group 1, then the element immediately preceding it in the same period is a noble gas (Group 18), or an element from the previous period (Group 17). A noble gas (Group 18) has an atomic number $Z_{\text{NG}}$. The next element, the alkali metal (Group 1), has $Z_{\text{NG}}+1$. If $Z_{\text{Z}}$ is an alkali metal, then $Z_{\text{Z}}-1$ is a noble gas. So, Y ($Z_{\text{Y}}=a+1$) must be a noble gas (Group 18), and X ($Z_{\text{X}}=a$) must be a halogen (Group 17).

Step 3: Analyze the nature of the elements X and Z.
Z is an alkali metal (Group 1, low ionization energy, high tendency to lose $e^-$ to form $Z^+$).
X is a halogen (Group 17, high electron affinity, high tendency to gain $e^-$ to form $X^-$).
Alkali metals are typical metals, and halogens are typical non-metals.

Step 4: Determine the nature of the bond between X and Z.
A compound formed between a metal (Z) and a non-metal (X), where there is a large difference in electronegativity, will involve the transfer of electrons and result in an electrostatic attraction between the resulting ions.
The bond formed by the electrostatic attraction between $Z^+$ and $X^-$ is an ionic bond.
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