Question:
The area of four walls of a room whose length and height are \(22\) m and \(6.5\) m respectively is \(442\) sq.m. The area of the floor in sq.m. is
The area of four walls of a room whose length and height are \(22\) m and \(6.5\) m respectively is \(442\) sq.m. The area of the floor in sq.m. is
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For four walls, always use \(2h(l+b)\). Floor area is simply \(l\times b\).
Updated On: Jul 15, 2026
- \(246\)
- \(256\)
- \(264\)
- \(164\)
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The Correct Option is C
Solution and Explanation
Concept:
Area of four walls:
\[
=2h(l+b)
\]
where:
\[
l=22,\quad h=6.5
\]
Step 1: Substitute values.
\[ 2(6.5)(22+b)=442 \] \[ 13(22+b)=442 \]
Step 2: Find breadth.
\[ 22+b=\frac{442}{13} \] \[ 22+b=34 \] \[ b=12 \]
Step 3: Find floor area.
Floor area: \[ l\times b \] \[ =22\times12 \] \[ =264 \] Thus, the area of the floor is: \[ \boxed{264} \]
Step 1: Substitute values.
\[ 2(6.5)(22+b)=442 \] \[ 13(22+b)=442 \]
Step 2: Find breadth.
\[ 22+b=\frac{442}{13} \] \[ 22+b=34 \] \[ b=12 \]
Step 3: Find floor area.
Floor area: \[ l\times b \] \[ =22\times12 \] \[ =264 \] Thus, the area of the floor is: \[ \boxed{264} \]
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