Question:

The area of a sector of a circle is \(110\text{ cm}^2\) and the central angle of the sector is \(56^\circ\). Find the radius of the circle. Take \(\pi = \dfrac{22}{7}\).

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For sector problems: \[ \text{Sector Area}= \frac{\theta}{360}\pi r^2 \] Simplify fractions early to avoid large calculations.
Updated On: May 27, 2026
  • \(35\text{ cm}\)
  • \(20\text{ cm}\)
  • \(25\text{ cm}\)
  • \(15\text{ cm}\)
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The Correct Option is D

Solution and Explanation

Concept: The area of a sector is given by: \[ \text{Area of Sector} = \frac{\theta}{360}\pi r^2 \] where:
  • \(\theta\) = central angle
  • \(r\) = radius


Step 1:
Substitute the given values. Given: \[ \text{Area} = 110\text{ cm}^2 \] \[ \theta = 56^\circ \] \[ \pi = \frac{22}{7} \] Thus, \[ 110 = \frac{56}{360}\times\frac{22}{7}\times r^2 \]

Step 2:
Simplify the fraction. \[ 110 = \frac{7}{45}\times\frac{22}{7}\times r^2 \] \[ 110 = \frac{22}{45}r^2 \]

Step 3:
Solve for \(r^2\). \[ r^2 = 110\times\frac{45}{22} \] \[ = 5\times45 \] \[ = 225 \] \[ r = \sqrt{225} \] \[ r = 15 \] Hence, \[ \boxed{15\text{ cm}} \]
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