Question

The angular resolution of a 10 cm diameter telescope at a wavelength of 5000 $\mathring{A}$ is of the order of

• A. ${10}^6 rad $
• B. ${10}^{-2} rad $
• C. ${10}^{-4} rad $
• D. ${10}^{-6} rad $

Answer 1

The Correct Option is A

$R.P = \frac{1}{\delta \theta}$
The angular resolution, $\delta \theta = \frac{ 1.22 \lambda }{D}$
$ = \frac{ 1.22 \times 5000 \times {10}^ {-8 }}{ 0.1} = 6.1 \times {10}^{-4} = {10}^{-4}$