Question:
The angle made by the vector $(2\hat{i} + 2\hat{j})$ with X-axis is
The angle made by the vector $(2\hat{i} + 2\hat{j})$ with X-axis is
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If the $\hat{i}$ and $\hat{j}$ coefficients are equal, the vector perfectly bisects the quadrant at $45^{\circ}$.
Updated On: Jul 4, 2026
- $45^{0}$
- $60^{0}$
- $90^{0}$
- $120^{0}$
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The Correct Option is A
Solution and Explanation
Step 1: Concept
For a vector $\vec{V} = x\hat{i} + y\hat{j}$, the angle $\theta$ with the X-axis is given by $\tan \theta = y/x$.
Step 2: Meaning
Here, the X-component ($x$) is 2 and the Y-component ($y$) is 2.
Step 3: Analysis
$\tan \theta = 2/2 = 1$.
Step 4: Conclusion
Since $\tan 45^{\circ} = 1$, the angle made with the X-axis is $45^{\circ}$. Final Answer: (A)
For a vector $\vec{V} = x\hat{i} + y\hat{j}$, the angle $\theta$ with the X-axis is given by $\tan \theta = y/x$.
Step 2: Meaning
Here, the X-component ($x$) is 2 and the Y-component ($y$) is 2.
Step 3: Analysis
$\tan \theta = 2/2 = 1$.
Step 4: Conclusion
Since $\tan 45^{\circ} = 1$, the angle made with the X-axis is $45^{\circ}$. Final Answer: (A)
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