Solution:
Carrier signal: $15 \sin(1000 \pi t)$
Modulating signal: $10 \sin(4 \pi t)$
The general form of a sinusoidal wave is $A \sin(2 \pi f t)$, where $A$ is the amplitude, $f$ is the frequency, and $t$ is time.
1. Carrier signal frequency $(f_c)$:
$$ 2 \pi f_c = 1000 \pi $$ $$ f_c = \frac{1000 \pi}{2 \pi} = 500 \text{ Hz} $$
2. Modulating signal frequency $(f_m)$:
$$ 2 \pi f_m = 4 \pi $$ $$ f_m = \frac{4 \pi}{2 \pi} = 2 \text{ Hz} $$
In amplitude modulation, the modulated signal contains the carrier frequency and two sideband frequencies:
Carrier frequency $(f_c) = 500 \text{ Hz}$
Lower sideband frequency $(f_c - f_m) = 500 \text{ Hz} - 2 \text{ Hz} = 498 \text{ Hz}$
Upper sideband frequency $(f_c + f_m) = 500 \text{ Hz} + 2 \text{ Hz} = 502 \text{ Hz}$
The frequencies present in the amplitude modulated signal are:
500 Hz (1)
498 Hz (4)
502 Hz (5)
Therefore, the correct answer is (4) (1), (4) and (5) only.
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,



What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)