The amphoteric oxide among $\mathrm{V}_2 \mathrm{O}_3, \mathrm{~V}_2 \mathrm{O}_4$ and $\mathrm{V}_2 \mathrm{O}_5$, upon reaction with alkali leads to formation of an oxide anion. The oxidation state of V in the oxide anion is :
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- + 4
- + 5
- + 3
- + 7
The Correct Option is B
Solution and Explanation
With alkali, $V_2O_5$ gives the vanadate ion: $V_2O_5 + 6NaOH \rightarrow 2Na_3VO_4 + 3H_2O$.
Let the oxidation state of V in $VO_4^{3-}$ be $x$: $x + 4(-2) = -3 \Rightarrow x = +5$.
The correct option is (2) $+5$.
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