Question:
The 2nd of June is a Thursday in a certain year. Which day of the week is the 3rd of July in that year?
The 2nd of June is a Thursday in a certain year. Which day of the week is the 3rd of July in that year?
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Find the total number of days between June 2 and July 3 (remember June has 30 days), then divide by 7 and use only the remainder to count forward from Thursday.
Updated On: Jul 22, 2026
- Thursday
- Friday
- Saturday
- Sunday
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The Correct Option is D
Solution and Explanation
Step 1: Note the given day and count the days to the target date.
We are told June 2 falls on a Thursday, and we need the day of the week for July 3 in the same year.
Step 2: Count the days from June 2 to July 3.
June has 30 days, so from June 2, moving forward exactly 30 days lands on July 2.
\[ \text{June 2} + 30 \text{ days} = \text{July 2} \]
July 3 is one day after July 2, so the total gap from June 2 to July 3 is
\[ 30+1=31 \text{ days} \]
Step 3: Convert the day gap into a shift in the day of the week.
Since the days of the week repeat every 7 days, only the remainder after dividing by 7 matters.
\[ 31 = 4\times7+3 \]
So the remainder is 3, meaning July 3 falls 3 days of the week after June 2.
Step 4: Apply the 3 day shift starting from Thursday.
Thursday plus 1 day is Friday, plus 2 days is Saturday, plus 3 days is Sunday.
Step 5: Rule out the other options.
(A) Thursday: This would be correct only if the gap were a multiple of 7 days, but the gap is 31 days, which is not a multiple of 7. Incorrect.
(B) Friday: This would match a 1 day shift, not the 3 day shift found here. Incorrect.
(C) Saturday: This would match a 2 day shift, one day short of the actual 3 day shift. Incorrect.
Final Answer:
July 3 falls exactly 3 weekdays after Thursday, June 2, which is a Sunday.
\[ \boxed{\text{Sunday}} \]
We are told June 2 falls on a Thursday, and we need the day of the week for July 3 in the same year.
Step 2: Count the days from June 2 to July 3.
June has 30 days, so from June 2, moving forward exactly 30 days lands on July 2.
\[ \text{June 2} + 30 \text{ days} = \text{July 2} \]
July 3 is one day after July 2, so the total gap from June 2 to July 3 is
\[ 30+1=31 \text{ days} \]
Step 3: Convert the day gap into a shift in the day of the week.
Since the days of the week repeat every 7 days, only the remainder after dividing by 7 matters.
\[ 31 = 4\times7+3 \]
So the remainder is 3, meaning July 3 falls 3 days of the week after June 2.
Step 4: Apply the 3 day shift starting from Thursday.
Thursday plus 1 day is Friday, plus 2 days is Saturday, plus 3 days is Sunday.
Step 5: Rule out the other options.
(A) Thursday: This would be correct only if the gap were a multiple of 7 days, but the gap is 31 days, which is not a multiple of 7. Incorrect.
(B) Friday: This would match a 1 day shift, not the 3 day shift found here. Incorrect.
(C) Saturday: This would match a 2 day shift, one day short of the actual 3 day shift. Incorrect.
Final Answer:
July 3 falls exactly 3 weekdays after Thursday, June 2, which is a Sunday.
\[ \boxed{\text{Sunday}} \]
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