Let the total number of employees be \( N \). The number of employees who drink coffee is 35% of \( N \), i.e., \( 0.35N \). The number of employees who drink tea is 40% of \( N \), i.e., \( 0.40N \). The number of employees who drink both coffee and tea is 10% of \( N \), i.e., \( 0.10N \). Using the principle of inclusion-exclusion to calculate the number of employees who drink either tea or coffee: \[ \text{Employees who drink tea or coffee} = (0.35N + 0.40N - 0.10N) = 0.65N \] The number of employees who drink neither tea nor coffee is the complement: \[ \text{Employees who drink neither} = N - 0.65N = 0.35N \] Thus, the percentage of employees who drink neither tea nor coffee is 35%. Therefore, the correct answer is option (C).
Final Answer: 35
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Given two operators \( \oplus \) and \( \odot \) on numbers \( p \text{ and } q \) such that \[ p \oplus q = \frac{p^2 + q^2}{pq} \text{and} p \odot q = \frac{p^2}{q}, \] if \( x \oplus y = 2 \odot 2 \), then \( x = \)