Question:

The 2nd of June is a Thursday in a certain year. Which day of the week is the 3rd of July in that year?

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Count the total number of days between the two dates and find the remainder after dividing by 7 to shift forward from Thursday.
Updated On: Aug 14, 2026
  • Thursday
  • Friday
  • Saturday
  • Sunday
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Question.
We know 2nd June falls on a Thursday. We need to find the day of the week for 3rd July of the same year.

Step 2: Key Formula or Approach.
The day of the week repeats every 7 days. To move from one date to another, count the total number of days between them, divide by 7, and the remainder tells us how many days of the week to move forward from the starting day.

Step 3: Detailed Explanation.
June has 30 days. From 2nd June to 2nd July is exactly 30 days later, since June has 30 days and adding 30 days to 2nd June lands exactly on 2nd July. From 2nd July to 3rd July is 1 more day. So the total gap from 2nd June to 3rd July is \(30 + 1 = 31\) days.
Now find the remainder when 31 is divided by 7: \(31 = 4 \times 7 + 3\), so the remainder is 3. This means 3rd July falls exactly 3 days of the week after 2nd June.
Starting from Thursday and counting 3 days forward: Thursday plus 1 day is Friday, plus 2 days is Saturday, plus 3 days is Sunday.

Step 4: Final Answer.
3rd July falls on a Sunday, which is option (D). \[ \boxed{\text{Sunday}} \]
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