Question:
The 288th term of the sequence a, b, b, c, c, c, d, d, d, d, ... is:
The 288th term of the sequence a, b, b, c, c, c, d, d, d, d, ... is:
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The k-th letter of the alphabet repeats k times; use the triangular number formula n(n+1)/2 to locate term 288.
Updated On: Jul 14, 2026
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The Correct Option is D
Solution and Explanation
k-th letter appears k times. Cumulative terms = n(n+1)/2. n=23: 276. n=24: 300. Since 276<288<=300, 288th term is the 24th letter = x.
Final Answer: x, option (4).
Final Answer: x, option (4).
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