Question:
Terminal velocity of a small sphere falling in viscous liquid varies with radius as:
Terminal velocity of a small sphere falling in viscous liquid varies with radius as:
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Terminal velocity increases with square of radius because gravitational force grows as r^3 while drag grows as r.
Updated On: Jun 10, 2026
- v_t r
- v_t r^2
- v_t 1r
- v_t 1r^2
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The Correct Option is B
Solution and Explanation
From Stokes’ Law:
\[
v_t = \frac{2r^2(\rho - \sigma)g}{9\eta}
\]
So,
\[
v_t \propto r^2
\]
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