Question

steady current of 1.25 A is passed through an electrochemical cell for 1.5 h using a 12 V battery. The total charge, Q, drawn during this process is __________ Coulombs. (round off to the nearest integer)

Answer 1

Correct Answer: 6750

To find the total charge \( Q \) drawn during the process, we use the formula: 
\( Q = I \times t \), where \( I \) is the current in Amperes and \( t \) is the time in seconds. 
Given \( I = 1.25 \) A and \( t = 1.5 \) h, we need to convert the time from hours to seconds. There are 3600 seconds in an hour, so \( t = 1.5 \times 3600 = 5400 \) s.
Substitute these values into the formula: 
\( Q = 1.25 \, \text{A} \times 5400 \, \text{s} = 6750 \, \text{C} \).
The calculated charge is \( 6750 \, \text{C} \)