Statement-I: Glucose exists in two anomeric. Statement-II: In open chain structure at C-3, C-4, C-5, glucose and fructose have identical configuration.
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Glucose and fructose have identical configurations at C-3, C-4, and C-5 in their open chain forms. The difference in their structures lies at the C-2 position.
Statement I is correct but Statement II is incorrect
Statement I is incorrect but Statement II is correct
Both Statement I and Statement II are incorrect
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The Correct Option isA
Solution and Explanation
Step 1: Analyze Statement I.
Glucose exists in two anomeric forms: one in which the \( \text{OH} \) group on C-1 is on the opposite side of the CH2OH group (alpha anomer) and the other in which the \( \text{OH} \) group on C-1 is on the same side as the CH2OH group (beta anomer). These are two anomeric forms of glucose. Hence, Statement I is correct. Step 2: Analyze Statement II.
In the open-chain structure of glucose and fructose, the configurations at C-3, C-4, and C-5 are identical. In both glucose and fructose, the configuration of the hydroxyl group on C-3, C-4, and C-5 is similar, and they differ at C-2. Therefore, Statement II is also correct. Step 3: Conclusion.
Since both Statement I and Statement II are correct, the correct answer is option (A). Final Answer: (A) Both Statement I and Statement II are correct.
