Given below are two statements:
Statement I : Acceleration due to earth's gravity decreases as you go 'up' or 'down' from earth's surface
Statement II : Acceleration due to earth's gravity is same at a height '\(h\)' and depth ' \(d\) ' from earth's surface, if \(h = d\).
In the light of above statements, Choose the most appropriate answer form the options given below
• Statement I: The acceleration due to gravity (g') decreases when moving away from the earth's surface either upwards or downwards. The formulae for variations are:
\[g' = g\left(1 - \frac{2h}{R}\right)\] (for height h above surface)
\[g' = g\left(1 - \frac{d}{R}\right)\] (for depth d below surface)
Both variations indicate a decrease in g.
• Statement II: At equal height h and depth d (h = d), the values of g' are not the same. This is because g decreases faster as we go up (due to the inverse square law) compared to going down (due to linear variation inside the earth).
Thus, Statement I is correct, and Statement II is incorrect.

A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,



What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
In the real world, everything is always in motion. Objects move at a variable or a constant speed. When someone steps on the accelerator or applies brakes on a car, the speed of the car increases or decreases and the direction of the car changes. In physics, these changes in velocity or directional magnitude of a moving object are represented by acceleration.
