Statement 1:
Boiling point order is in decreasing order due to decreasing Vanderwaal's forces. Statement 2:
P-dichlorobenzene has more melting point value due to its symmetric structure than O-dichlorobenzene while it has less boiling point than O-dichlorobenzene.
Statement I is correct but Statement II is incorrect.
Statement I is incorrect but Statement II is correct.
Both Statement I and Statement II are incorrect.
Show Solution
Verified By Collegedunia
The Correct Option isA
Solution and Explanation
Step 1: Understanding Statement I.
Statement I talks about the boiling point of molecules. As the molecular size increases, the London dispersion forces (a type of van der Waals force) also increase. Thus, larger molecules have higher boiling points due to stronger intermolecular forces. The order of boiling points here is I > CH\(_3\)I based on increasing molecular size and van der Waals forces. This is a correct statement.
Step 2: Understanding Statement II.
Statement II discusses the effect of symmetry on the melting and boiling points of dichlorobenzene isomers. P-dichlorobenzene has a more symmetrical structure compared to O-dichlorobenzene, which leads to better packing and thus a higher melting point. However, due to the symmetry, the molecule has less surface area for intermolecular interactions, resulting in a lower boiling point than O-dichlorobenzene. This is also correct.
Step 3: Conclusion.
Both Statement I and Statement II are correct. Hence, the correct answer is (A).
Final Answer: Both Statement I and Statement II are correct.
