Question:

Six male friends A, B, C, D, E and F are married to R, S, U, V, T and W and not necessarily is same order. Following facts are additionally known about them: - R and S are A's sisters Neither R nor T are wives of C W is wife of E V is wife of B D is not married to R, S or T Who is A's wife?

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Use elimination based on relationships and available optionss. Sisters cannot marry their brother.
Updated On: Mar 30, 2026
  • U
  • S
  • R
  • V
  • T
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The Correct Option is A

Solution and Explanation


Step 1:
R and S are A's sisters, so they are female and not married to A (since they are his sisters). So A's wife is not R or S.
Step 2:
W is wife of E, so W is taken. V is wife of B, so V is taken.
Step 3:
Neither R nor T are wives of C. So C's wife is not R or T. D is not married to R, S, or T.
Step 4:
Wives available: R, S, U, V, T, W. V and W are taken by B and E. So remaining wives for A, C, D, F: R, S, U, T.
Step 5:
A's wife cannot be R or S (sisters), so A's wife must be U or T. C's wife cannot be R or T, so C's wife can be S or U. D's wife cannot be R, S, T, so D's wife can be U only (since V and W are taken).
Step 6:
If D's wife is U, then A cannot have U. So A's wife must be T. Then C's wife can be S. F gets R.
Step 7:
So A's wife is T.
Step 8:
Final Answer: T.
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