Shown below is a strip of paper which is folded multiple times. How many red pawns are placed on the same side of the paper as the blue pawn? 
The problem requires determining how many red pawns are placed on the same side of the paper as the blue pawn in the given figure.
Analysis
The figure represents a strip of paper folded multiple times, creating a series of alternating sides for the red and blue pawns. To determine how many red pawns are on the same side as the blue pawn, we must carefully observe the placement of the pawns relative to the blue pawn.
Steps to Solve
The blue pawn is placed on one specific side of the folded paper. Every alternate pawn on the paper will be on the opposite side due to the folding pattern.
Starting from the blue pawn, we trace along the strip of paper and identify the red pawns that are placed on the same side as the blue pawn.
Counting the Red Pawns
Observing the placement in the figure, there are a total of 9 red pawns on the same side of the paper as the blue pawn.
The remaining red pawns are on the opposite side.
Conclusion
The number of red pawns on the same side of the paper as the blue pawn is 9.
Folded strip puzzles turn into a side tracking exercise once you treat each fold as a flip. Instead of reading the picture as one flat line, imagine unfolding it back into segments. Label every segment "Side A" or "Side B" based on which way it faces after each crease.
Start at the blue pawn's segment and call it Side A. Every fold crossed while moving away from the blue pawn flips the facing side. So the segment right after one fold is Side B, the next flips back to Side A, and so on in strict alternation. Marking every red pawn's segment this way and counting only the Side A pawns, the ones sharing the blue pawn's facing, gives 9 red pawns. The rest fall on Side B, opposite the blue pawn.
the answer is 9








