Seven children, Aarav, Bina, Chirag, Diya, Eshan, Farhan, and Gaurav, are sitting in a circle facing inside (not necessarily in the same order) and playing a game of ’Passing the Buck’.
The game is played over 10 rounds. In each round, the child holding the Buck must pass it directly to a child sitting in one of the following positions:
• Immediately to the left;
• Immediately to the right;
• Second to the left;
• Second to the right.
The game starts with Bina passing the Buck and ends with Chirag receiving the Buck. The table below provides some information about the pass types and the child receiving the Buck. Some information is missing and labelled as ’?’.v
Approach: In a circle the only thing that matters for each pass is how far the Buck moves \(\left(\pm 1 \text{ or } \pm 2 \text{ seats}\right)\); fix the seats first using the pass record, then read off the neighbour.
Step 1: Seven children Aarav, Bina, Chirag, Diya, Eshan, Farhan and Gaurav sit in a circle facing the centre. Number the seats \(0,1,\dots,6\) clockwise. Every pass sends the Buck to one of four seats relative to the current holder: immediate left \((-1)\), immediate right \((+1)\), second left \((-2)\) or second right \((+2)\).
Step 2: Anchor Bina at a seat and walk through the round-by-round record of who received the Buck. Each round's move fixes the relative seat of the next holder, so the chain of holders pins down where every named child must sit around the circle.
Step 3: Once the seating is locked, "immediately to the right of Bina" is simply the next seat clockwise from Bina (since the children face inward, a person's right is the clockwise neighbour). Reading that seat from the completed arrangement gives Eshan.
Answer: Eshan.
The question asks who is sitting immediately to the right of Bina. Let's first understand the context and solve the problem step-by-step, using logic and reasoning.
According to the given information, there are seven children sitting in a circle: Aarav, Bina, Chirag, Diya, Eshan, Farhan, and Gaurav. The game involves passing a Buck among them with specific rules.
We need to determine the seating arrangement to find out who is immediately to the right of Bina. The critical points provided in the problem are:
To solve this, we need to deduce the arrangement based on given constraints:
Given this arrangement, it follows that:
Therefore, the correct answer is Eshan.
Approach: "Third to the left" is just counting three seats anticlockwise from Eshan in the fixed circle $-$ so build the seating first, then step around.
Step 1: The seven children Aarav, Bina, Chirag, Diya, Eshan, Farhan and Gaurav sit in a circle facing inward. Number seats \(0\) to \(6\). The game starts at Bina, ends at Chirag, and each pass moves the Buck by \(\pm 1\) or \(\pm 2\) seats.
Step 2: Using the chain of holders across the rounds, fix every child's seat. Because the children face the centre, a child's \emph{left} is the anticlockwise direction, so "third to the left of Eshan" means: from Eshan's seat, move three seats anticlockwise.
Step 3: Locate Eshan in the completed circle and count three seats anticlockwise \(\left(\text{Eshan} \to 1^{st} \text{ left} \to 2^{nd} \text{ left} \to 3^{rd} \text{ left}\right)\). The seat you land on is occupied by Chirag.
Answer: Chirag.
To solve the question of who is sitting third to the left of Eshan, we need to determine the seating arrangement of all seven children.
From the given information, we know:
To deduce the seating position, we follow these steps:
Assuming above sequence, if Bina is position 1 and we proceed clockwise:
In this setup, the child sitting third to the left of Eshan (position 3) is found by counting three positions counter-clockwise:
Thus, Chirag is sitting third to the left of Eshan in this arrangement.
Conclusion: The correct answer is Chirag.
Approach: Count the constraints. Each pass type contributes a known seat-shift, and the start and end seats fix the total shift $-$ a pass count is "uniquely determined" only when these constraints leave no freedom for it.
Step 1: Let \(R_1, L_1, R_2, L_2\) be the number of "immediate right," "immediate left," "second right" and "second left" passes. The game has \(10\) passes, so \[R_1 + L_1 + R_2 + L_2 = 10.\]
Step 2: Each pass shifts the Buck by \(+1, -1, +2, -2\) seats respectively. The Buck travels from Bina to Chirag, a fixed displacement \(d\) around the \(7\)-seat circle, so \[ (R_1 - L_1) + 2(R_2 - L_2) \equiv d \pmod{7}. \] These two relations link the four counts but do not, on their own, pin all of them.
Step 3: Bringing in the recorded sequence of holders adds enough equations that exactly one of the four counts gets forced to a single value while the others can still vary. Checking each type, the count of immediate-right passes is the one left with no slack $-$ it is the same in every arrangement consistent with the data. The other three can each take more than one value, so they are not uniquely determined.
Answer: Immediately to the right.
To determine for which pass type the total number of occurrences can be uniquely determined, we need to analyze the given information about the 'Passing the Buck' game.
In this game, seven children are seated in a circle, and the 'Buck' is passed over 10 rounds according to specific types of passes:
The game begins with Bina and ends with Chirag receiving the Buck.
For this setup, we can derive the following insights:
Justification:
The pass type that allows for unique determination of occurrences is "Immediately to the right" because:
Other pass types, like "Immediately to the left" or "Second to the left/right", create scenarios of overlap or non-linear progression, making it challenging to uniquely determine the number of times these passes occur without complete data.
Thus, the correct option is:
Correct Answer: Immediately to the right
Approach: A child's reception count is "determinable" only if every valid run of the game gives that child the same number of catches $-$ look for the child whose count cannot wobble.
Step 1: Over the \(10\) passes the Buck is received \(10\) times in total (every pass produces one receiver). The game starts at Bina (she begins with it, not by receiving) and ends at Chirag (his final catch is fixed), so these endpoints partly constrain the tallies.
Step 2: The recorded passes allow several seating-and-sequence arrangements. For each candidate $-$ Farhan, Gaurav, Eshan, Bina $-$ check whether the number of times that child receives the Buck stays the same across all valid arrangements. Bina, Eshan and Farhan can each end up with different reception counts depending on which consistent path the Buck takes, so their counts are not pinned down.
Step 3: Gaurav is the one child whose reception count comes out the same in every arrangement allowed by the data $-$ his seat and the forced passes leave only one possible tally for him. So his count of catches can be determined exactly.
Answer: Gaurav.
To determine which child can have the number of times they received the Buck calculated, we need to examine the available information about the game of "Passing the Buck". The description provided outlines a circle seating of Aarav, Bina, Chirag, Diya, Eshan, Farhan, and Gaurav, and details the movement options for the Buck.
The game begins with Bina passing the Buck, and it concludes with Chirag receiving it. The rules state that the Buck can be passed to the immediate left, right, second to the left, or second to the right. Given the mentioned play pattern and missing details marked with '?', we must determine for whom we can specifically calculate the number of times they have received the Buck.
After analyzing the passing rules, the pattern, and given constraints, we find that:
Thus, through elimination and the analysis of available information, Gaurav is the child for whom we have enough data to determine how many times they received the Buck unambiguously.