Step 1: Understanding the Concept:
This question requires finding the three roots of a cubic polynomial equation.
This can be solved by testing candidates using the rational root theorem, factoring the polynomial, or using Vieta's formulas for cubic equations.
Step 2: Detailed Explanation:
Let us use Vieta's formulas to evaluate the roots. For any cubic equation of the form:
\[ ax^3 + bx^2 + cx + d = 0 \]
with roots \( \alpha \), \( \beta \), and \( \gamma \), the formulas state:
1. Sum of the roots:
\[ \alpha + \beta + \gamma = -\frac{b}{a} \]
2. Product of the roots taken two at a time:
\[ \alpha\beta + \beta\gamma + \alpha\gamma = \frac{c}{a} \]
3. Product of the roots:
\[ \alpha\beta\gamma = -\frac{d}{a} \]
Let us extract the coefficients from our cubic equation:
\[ x^3 - 23x^2 + 142x - 120 = 0 \]
Here, \( a = 1 \), \( b = -23 \), \( c = 142 \), and \( d = -120 \).
- The sum of the roots must be:
\[ \alpha + \beta + \gamma = -\frac{-23}{1} = 23 \]
- The product of the roots must be:
\[ \alpha\beta\gamma = -\frac{-120}{1} = 120 \]
Let us test the given options against these two simple conditions:
- Option (A): \( 1, 10, 12 \)
- Sum of roots: \( 1 + 10 + 12 = 23 \) (Matches!)
- Product of roots: \( 1 \times 10 \times 12 = 120 \) (Matches!)
Since both conditions are satisfied, these must be the correct roots.
- Option (B): \( -1, 10, 12 \)
- Sum of roots: \( -1 + 10 + 12 = 21 \neq 23 \). (Incorrect)
- Option (C): \( 1, -10, 12 \)
- Sum of roots: \( 1 - 10 + 12 = 3 \neq 23 \). (Incorrect)
- Option (D): \( -1, -10, -12 \)
- Sum of roots: \( -1 - 10 - 12 = -23 \neq 23 \). (Incorrect)
Therefore, only the roots in Option (A) satisfy the cubic polynomial equation.
Step 3: Final Answer:
The roots of the equation are \( 1, 10, 12 \).
Therefore, the correct choice is Option (A).