Comprehension

DIRECTIONS for the following questions: These questions are based on the situation given below: A young girl Roopa leaves home with \(x\) flowers, goes to the bank of a nearby river. On the bank of the river, there are four places of worship, standing in a row. She dips all the \(x\) flowers into the river. The number of flowers doubles. Then she enters the first place of worship, offers \(y\) flowers to the deity. She dips the remaining flowers into the river, and again the number of flowers doubles. She goes to the second place of worship, offers \(y\) flowers to the deity. She dips the remaining flowers into the river, and again the number of flowers doubles. She goes to the third place of worship, offers \(y\) flowers to the deity. She dips the remaining flowers into the river, and again the number of flowers doubles. She goes to the fourth place of worship, offers \(y\) flowers to the deity. Now she is left with no flowers in hand.

Question: 1

If at the time Roopa moves out from her house, she has 30 flowers, then how many did she present to each deity?

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In problems involving doubling or halving quantities, work through each step logically and keep track of changes in the number of items at each stage.
Updated On: Oct 29, 2026
  • 30
  • 31
  • 32
  • 33
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The Correct Option is C

Solution and Explanation

Let the number of flowers Roopa has when she starts be \( X \). As she presents flowers to the deities, the number of flowers doubles each time she dips them in the river. Let’s follow the pattern step by step, starting with the number of flowers she presents to the first deity and moving through each deity. The correct number of flowers presented is calculated based on the doubling pattern and the starting value of \( X \). Since we know she has 30 flowers, this gives us a final answer of 32 flowers.
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Question: 2

The minimum number of flowers that could be offered to each deity is:

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Write the number of flowers after each of the four dips and set the final number to 0 to get a relation between x and y; both must be positive whole numbers.
Updated On: Nov 4, 2026
  • 0
  • 15
  • Cannot be determined
  • 16
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The Correct Option is D

Solution and Explanation

Step 1: Track the flowers:
Start with \(x\). After dip 1 and offering: \(2x - y\). After dip 2 and offering: \(2(2x - y) - y = 4x - 3y\). After dip 3: \(8x - 7y\). After dip 4: \(16x - 15y\).

Step 2: Condition for no flowers left:
\(16x - 15y = 0\), so \(16x = 15y\). Since 15 and 16 have no common factor, \(x\) must be a multiple of 15 and \(y\) a multiple of 16: \(x = 15k\), \(y = 16k\).

Step 3: Smallest positive offering:
For \(k = 1\): \(x = 15\) and \(y = 16\). (Check: 30 - 16 = 14; 28 - 16 = 12; 24 - 16 = 8; 16 - 16 = 0.) The value 0 (\(k = 0\)) would mean nobody ever offered anything, which is not the situation described; so the minimum is 16.

Final Answer:
The correct option is (4): 16
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Question: 3

The minimum number of flowers with which Roopa leaves home is:

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After the four dips and offerings the flowers left are \(16x - 15y\); set this to zero and find the smallest positive whole-number solution.
Updated On: Nov 4, 2026
  • 16
  • Cannot be determined
  • 0
  • 15
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collegedunia
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The Correct Option is D

Solution and Explanation

Step 1: Track the flowers:
After each dip-and-offer stage the number is \(2x - y\), \(4x - 3y\), \(8x - 7y\), \(16x - 15y\).

Step 2: Condition:
She has nothing left, so \(16x = 15y\). Hence \(x\) is a multiple of 15 and \(y\) a multiple of 16: \(x = 15k\), \(y = 16k\).

Step 3: Smallest start:
The smallest positive \(x\) is 15 (with \(y = 16\)). Check: 15 gives 30, offer 16 leaves 14; 28 - 16 = 12; 24 - 16 = 8; 16 - 16 = 0. The value 0 is the trivial case where she carries no flowers at all, which does not fit the story of her offering flowers.

Final Answer:
The correct option is (4): 15
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