Step 1: Property of a parallel combination.
When two resistances are connected in parallel, both are joined between the same two nodes. Therefore the same potential difference appears across each of them, equal to the battery voltage \( V \).
Step 2: Check the potential drop.
Since both resistors share the same two terminals, the potential drop across the \( 10\ \Omega \) resistor equals the potential drop across the \( 15\ \Omega \) resistor, both \(= V\). This makes option (iv) correct and option (iii) wrong.
Step 3: Check the currents.
By Ohm's law \( I = V/R \). So \( I_{10} = V/10 \) and \( I_{15} = V/15 \). Since \( 10 < 15 \), the current in the \( 10\ \Omega \) resistor is larger, not smaller, and the two currents are not equal. This rules out options (i) and (ii).
Step 4: Conclusion.
The potential drop across both resistances is the same.
\[\boxed{V_{10\Omega} = V_{15\Omega} = V}\]