Refer to the circuit diagram given in the figure, which of the following observations are correct?

Observations:
A. Total resistance of circuit is 6 Ω
B. Current in Ammeter is 1 A
C. Potential across AB is 4 Volts
D. Potential across CD is 4 Volts
E. Total resistance of the circuit is 8 Ω
Choose the correct answer from the options given below:
To solve the problem, let's analyze the given circuit and observations step-by-step.
The circuit consists of a battery of 6V and three resistors each of 4 Ω.
Conclusions:
The correct answer is: A, B and D only
To determine the correct observations, we need to analyze the circuit and calculate each component:
Step 1: Total Resistance of the Circuit
The total resistance is given by the sum of individual resistances in the circuit. If the resistors are in series, add them up directly. If they are in parallel, use the formula:
1/Rtotal = 1/R1 + 1/R2 + ... + 1/Rn
Let's assume we have identified the resistors R1, R2, ... from the diagram. Verify if the total resistance is 6 Ω or 8 Ω by calculation.
Step 2: Current in the Ammeter
Using Ohm's Law, I = V/R, where V is the voltage and R is the total resistance calculated. Verify if the current is indeed 1 A.
Step 3: Potential Across AB and CD
Calculate the potential difference across each segment using Ohm's Law: V = I * R. Verify if segments AB or CD have 4 Volts across them.
After calculating:
Therefore, observations A, B, and D are correct, leading us to the conclusion:
Correct Options: A, B, and D only
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,

What is the current through the battery in the circuit shown below? 

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)