| Sector Wise Installed Capacity in MW | ||||
| Year | Thermal | Hydel | Nuclear | Total |
| 1990 | 7900 | 6390 | 420 | 14710 |
| 1991 | 8200 | 6610 | 420 | 15230 |
| 1992 | 8900 | 6780 | 420 | 16100 |
| 1993 | 9100 | 6965 | 640 | 16700 |
| 1994 | 10150 | 7530 | 640 | 18320 |
| 1995 | 11000 | 8500 | 640 | 20140 |
| 1996 | 12000 | 9200 | 640 | 21840 |
| 1997 | 13000 | 9880 | 640 | 23520 |
| 1998 | 15200 | 10200 | 800 | 26200 |
| 1999 | 16700 | 104500 | 800 | 27950 |
| 2000 | 19000 | 11000 | 800 | 30800 |
In this question we have to check the growth year wise,
For 1991: 6610-6390 / 6390 = 3.44\(\%\)
In the table, we can clearly see that the least difference year is 1994 and 1995
For the year 1995 = \(\frac{8500-7530}{7530}\)
= 12.88 \(\%\)
The correct option is (D)
The production of Nuclear power in the year 2000 = 800
The Total capacity in the year 2000 = 30800
Percentage share = \(\frac{800}{30800}\) = 0.0259
Percentage share = 2.59\(\%\)
The correct option is (B)
If the total power generated in thermal units be 40\(\%\) of the installed capacity, in hydel units be 50\(\%\) of the installed capacity and in nuclear be 90\(\%\) of the installed capacity, the total power generation in 1998 would be
In question given that total power generated is
Total power generated = 40\(\%\) of Thermal power+ 50\(\%\) of Hydel power+ 90\(\%\) of Nuclear power
Thermal Power = 15200 MW
Hydel Power = 10200 MW
Nuclear Power = 800 MW
Power generated = \(\frac{40}{100}\) × 15200 + \(\frac{50}{100}\) × 10200 + \(\frac{90}{100}\) × 800
= 11900 MW
The correct option is (B)
Thermal Installed capacity in year 1990 = 7900
Total installed capacity in year 1990 = 14710
Percentage share of thermal energy in total capacity = \(\frac{Thermal}{Total\ Energy\ Produced}\)
Percentage share of thermal in total installed capacity = \(\frac{7900}{14710}\)
= 53.7\(\%\) approx. 54\(\%\)
The correct option is (D)
Thermal capacity in 1991 = 8200
Thermal capacity in 1999 = 16700
Growth formula = \(\frac{Final\ Growth - Initial\ Growth}{Initial Growth}\)
Growth = \(\frac{16700-8200}{8200}\) = 1.03
Growth = 103\(\%\)
The correct option is (D)
The table provided displays the estimated cost (in lakh) for the construction of a canal between two points. Based on the information in the table, answer the questions that follow.
The following table gives the marks obtained by six students in six different subjects in an examination. The maximum marks for each subject are given in the brackets. Answer the questions that follow.
Consider the provided scenario and answer the following questions based on the given information.

