The Correct Option is B
Solution and Explanation
The given reaction is an elimination reaction using alcoholic KOH as the base. Under such conditions, the reaction favors the formation of an alkene via the E2 mechanism. The elimination occurs by the removal of the ff-hydrogen, leading to the formation of the most stable (more substituted) alkene as the major product. In this case, the product formed is a highly substituted alkene, making option (2) the correct answer.
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