





Step 1: Nucleophilic substitution (\( S_N2 \)) with dimethylamine (\( \text{Me}_2\text{NH} \)): The bromine atom at one of the carbons is replaced by the nucleophile (\( \text{Me}_2\text{N} \)) via an \( S_N2 \) mechanism. This forms an intermediate with a quaternary amine at the adjacent carbon.
Step 2: Deprotonation: The positively charged intermediate loses a proton (\(-\text{H}^+\)) to stabilize the structure, forming an alkene.
Step 3: Second \( S_N2 \) reaction: The second equivalent of dimethylamine attacks the adjacent carbon-bromine bond, substituting the bromine atom with another \( \text{Me}_2\text{N} \) group.
The final product contains two \( \text{Me}_2\text{N} \) groups attached to the cyclopentane ring at adjacent positions.
The above mechanism is valid for both cis and trans isomers. Hence, the products are the same for both.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are




In the following substitution reaction: 
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)