Question

Predict expression for \( \alpha \) in terms of \( K_{eq} \) and concentration
C: \( A_2B_3 \, (aq) \rightleftharpoons 2A^{3+} (aq) + 3B^{2-} (aq) \)

• A. \( \left( \frac{K_{eq}}{108C^4} \right)^{1/5} \)
• B. \( \left( \frac{K_{eq}}{5C^4} \right)^{1/5} \)
• C. \( \left( \frac{4K_{eq}}{5C^4} \right)^{1/5} \)
• D. \( \left( \frac{9K_{eq}}{5C^4} \right)^{1/5} \)

Hint:

For reactions at equilibrium, the expression for \( \alpha \) depends on the stoichiometry and equilibrium constant. Pay attention to the coefficients in the balanced equation.

Answer 1

The Correct Option is B

The expression for \( \alpha \) in terms of the equilibrium constant \( K_{eq} \) and concentration is derived from the general relation for chemical equilibria, taking into account the stoichiometry of the reaction. Step 1: Deriving the expression for \( \alpha \).
The relationship involves balancing the concentrations of the reactants and products. For the given reaction, we use the formula for equilibrium constants, and considering the stoichiometric coefficients, the correct form of the expression is \( \left( \frac{K_{eq}}{5C^4} \right)^{1/5} \). Step 2: Conclusion.
Therefore, the correct expression for \( \alpha \) in terms of \( K_{eq} \) and concentration is option (B). Final Answer:} \( \left( \frac{K_{eq}}{5C^4} \right)^{1/5} \).