Step 1: Let the oxidation number of Mn be \( x \) in \( KMnO_4 \).
Step 2: Since \( K = +1 \) and \( O_4 = -8 \), the equation is: \[ 1 + x + (-8) = 0 \] \[ x = +7 \] Thus, the oxidation state of Mn in \( KMnO_4 \) is +7.
Identify and in the following reactions:
