Question:

Organize the given states of India in ascending order based on density of population according to 2011 Census. \[ \begin{aligned} A.&\ \text{Nagaland} B.&\ \text{Sikkim} C.&\ \text{Manipur} D.&\ \text{Mizoram} \end{aligned} \] Choose the correct answer from the options given below:

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Remember the densities: \[ \boxed{ \text{Sikkim} < \text{Mizoram} < \text{Nagaland} < \text{Manipur} } \] Mnemonic: “Small Hills before Manipur.”
Updated On: Jul 29, 2026
  • B, D, C, A
  • D, B, A, C
  • B, A, D, C
  • D, A, C, B
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The Correct Option is A

Solution and Explanation

Concept: According to the Census of India 2011, the population density (persons/\(\text{km}^2\)) of these states is approximately: \[ \begin{aligned} \text{Sikkim} &\rightarrow 86, \text{Mizoram} &\rightarrow 52, \text{Manipur} &\rightarrow 122, \text{Nagaland} &\rightarrow 119. \end{aligned} \]

Step 1:
Arrange from lowest to highest density. \[ \boxed{ \text{Mizoram} < \text{Sikkim} < \text{Nagaland} < \text{Manipur} } \]

Step 2:
Convert into letter sequence. \[ \boxed{ B \rightarrow D \rightarrow C \rightarrow A } \] Hence, \[ \boxed{\text{(A)}} \]
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