Question:

Number of stereo centers present in linear and cyclic structures of glucose are respectively :

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Open-chain glucose has 4 chiral carbons (C2-C5); on cyclisation C1 becomes a new chiral (anomeric) centre.
Updated On: Nov 5, 2026
  • 4 & 4
  • 4 & 5
  • 5 & 4
  • 5 & 5
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The Correct Option is B

Solution and Explanation

Open-chain glucose: CH2OH-CH(OH)-CH(OH)-CH(OH)-CH(OH)-CHO. C1 (CHO) and C6 (CH2OH) are not chiral; C2, C3, C4, C5 are chiral: 4 stereocentres.
In the cyclic (pyranose) form, hemiacetal formation turns C1 into a carbon bearing four different groups (H, OH, ring O, C2): the anomeric centre. So the cyclic form has C1, C2, C3, C4, C5 = 5 stereocentres.
Answer: (2) 4 & 5
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