Question:
Number of coulombs corresponding to \(1\text{ mol}\) of electrons approximately is equal to
Number of coulombs corresponding to \(1\text{ mol}\) of electrons approximately is equal to
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Charge of one mole of electrons is one Faraday, and \(1F\approx96500\text{ C}=9.65\times10^4\text{ C}\).
Updated On: May 7, 2026
- \(1.93\times10^5\)
- \(9.65\times10^4\)
- \(1.93\times10^4\)
- \(9.65\times10^5\)
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The Correct Option is B
Solution and Explanation
The charge carried by one mole of electrons is called one Faraday.
One Faraday is given by:
\[
F=N_Ae.
\]
Here,
\[
N_A=6.022\times10^{23}\text{ mol}^{-1}
\]
and
\[
e=1.602\times10^{-19}\text{ C}.
\]
Therefore,
\[
F=(6.022\times10^{23})(1.602\times10^{-19}).
\]
\[
F\approx 9.65\times10^4\text{ C}.
\]
Hence, one mole of electrons carries approximately:
\[
9.65\times10^4\text{ coulombs}.
\]
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