Question:
निम्नलिखित अभिक्रिया क्रम के लिए, सही विकल्प चुनिए :
निम्नलिखित अभिक्रिया क्रम के लिए, सही विकल्प चुनिए :
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Methyl ketones haloform reaction देकर carboxylate salt बनाते हैं।
Updated On: Jun 22, 2026
- यदि \(P\) अम्लीकरण पर एक कार्बोक्सिलिक अम्ल देता है, तो \(Q\) वायु और प्रकाश के संपर्क में आने पर एक विस्फोटक गैस देता है।
- \(P\) और \(Q\) दोनों कार्बोनिल यौगिक हैं।
- यदि \(P\) एक कार्बोक्सिलिक अम्ल का सोडियम लवण है, तो \(Q\) एक प्राथमिक ऐल्कोहॉल है।
- \(P\) और \(Q\) एरोमैटिक यौगिक हैं।
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Verified By Collegedunia
The Correct Option is B
Solution and Explanation
पद 1: प्रश्न को समझना
पहले Friedel-Crafts acylation और फिर haloform reaction हो रही है।
पद 2: मुख्य सूत्र या दृष्टिकोण
Step 1: \[ C_6H_6 + CH_3COCl \rightarrow C_6H_5COCH_3 \] (Acetophenone) Step 2: \[ CH_3CO-\text{ group} \] Haloform reaction देता है।
पद 3: विस्तृत व्याख्या
Products: \[ P=C_6H_5COONa \] (Sodium benzoate) \[ Q=CHCl_3 \] (Chloroform) दोनों carbonyl derivatives हैं।
पद 4: अंतिम उत्तर
अतः सही विकल्प (B) है।
पहले Friedel-Crafts acylation और फिर haloform reaction हो रही है।
पद 2: मुख्य सूत्र या दृष्टिकोण
Step 1: \[ C_6H_6 + CH_3COCl \rightarrow C_6H_5COCH_3 \] (Acetophenone) Step 2: \[ CH_3CO-\text{ group} \] Haloform reaction देता है।
पद 3: विस्तृत व्याख्या
Products: \[ P=C_6H_5COONa \] (Sodium benzoate) \[ Q=CHCl_3 \] (Chloroform) दोनों carbonyl derivatives हैं।
पद 4: अंतिम उत्तर
अतः सही विकल्प (B) है।
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