Question:

Negation of the statement :
\(\sqrt{5}\) is an integer or 5 is an irrational is :

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Apply De Morgan's law: \(\sim(p \lor q) = \sim p \land \sim q\).
Updated On: Nov 5, 2026
  • \(\sqrt{5}\) is not an integer and 5 is not irrational.
  • \(\sqrt{5}\) is irrational or 5 is an integer.
  • \(\sqrt{5}\) is an integer and 5 is irrational.
  • \(\sqrt{5}\) is not an integer or 5 is not irrational.
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The Correct Option is A

Solution and Explanation

Let p: \(\sqrt{5}\) is an integer, q: 5 is irrational. The statement is \(p \lor q\).
By De Morgan's law, \(\sim(p \lor q) \equiv (\sim p) \land (\sim q)\).
\(\sim p\): \(\sqrt{5}\) is not an integer; \(\sim q\): 5 is not irrational.
So the negation is '\(\sqrt{5}\) is not an integer and 5 is not irrational'.
Answer: (1) \(\sqrt{5}\) is not an integer and 5 is not irrational.
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