(i) \(\frac{2}{3}\) × 2 \(\frac{2}{3}\) = \(\frac{2}{3}\) × \(\frac{8}{3}\) = \(\frac{16}{9}\) = \(\frac{17}{9}\)
(ii) \(\frac{2}{7}\) × \(\frac{7}{9}\) = \(\frac{2}{9}\)
(iii) \(\frac{3}{8}\) × \(\frac{6}{4}\) = \(\frac{9}{16}\)
(iv) \(\frac{9}{5}\) × \(\frac{3}{5}\) = \(\frac{27}{5}\)= 1 \(\frac{2}{25}\)
(v) \(\frac{1}{3}\) × \(\frac{15}{8}\) = \(\frac{5}{8}\)
(vi) \(\frac{11}{2}\) × \(\frac{3}{10}\)= \(\frac{33}{20}\) = 1 \(\frac{13}{20}\)
(vii) \(\frac{4}{5}\)× \(\frac{12}{7}\) = \(\frac{48}{35}\) = 1 \(\frac{13}{35}\)


| So No | Base | Height | Area of parallelogram |
|---|---|---|---|
| a. | 20 cm | - | 246 \(cm^2\) |
| b. | - | 15 cm | 154.5 \(cm^2\) |
| c. | - | 8.4 cm | 48.72 \(cm^2\) |
| d. | 15.6 cm | - | 16.38 \(cm^2\) |
| Base | Height | Area of triangle |
|---|---|---|
| 15 cm | - | 87 \(cm^2\) |
| - | 31.4 mm | 1256 \(mm^2\) |
| 22 cm | - | 170.5 \(cm^2\) |

Find: (a) \(\frac{1}{2}\) of (i) 2 \(\frac{3}{4}\) (ii) 4 \(\frac{2}{9}\)
(b) \(\frac{5}{8}\) of (i) 3 \(\frac{5}{6}\) (ii) 9 \(\frac{2}{3}\)


| So No | Base | Height | Area of parallelogram |
|---|---|---|---|
| a. | 20 cm | - | 246 \(cm^2\) |
| b. | - | 15 cm | 154.5 \(cm^2\) |
| c. | - | 8.4 cm | 48.72 \(cm^2\) |
| d. | 15.6 cm | - | 16.38 \(cm^2\) |
| Base | Height | Area of triangle |
|---|---|---|
| 15 cm | - | 87 \(cm^2\) |
| - | 31.4 mm | 1256 \(mm^2\) |
| 22 cm | - | 170.5 \(cm^2\) |
