(a) 3 × 5 \(\frac{1}{5}\)= 3 × \(\frac{26}{5}\)= \(\frac{78}{5}\) = 15 \(\frac{3}{5}\)
(b) 5 × 6 \(\frac{3}{4}\) = 5 × \(\frac{27}{4}\) = \(\frac{135}{4}\)= 33 \(\frac{3}{4}\)
(c) 7 × 2\(\frac{1}{4}\)= 7 × \(\frac{9}{4}\)= \(\frac{63}{4}\) = 15\(\frac{3}{4}\)
(d) 4 × 6 \(\frac{1}{3}\)= 4 × \(\frac{19}{3}\) = \(\frac{76}{3}\) = 25 \(\frac{1}{3}\)
(e) 3 \(\frac{1}{4}\) × 6 = \(\frac{13}{4}\) × 6 = \(\frac{78}{4}\) = \(\frac{39}{2}\) = 19\(\frac{1}{2}\)
(f) 3 \(\frac{2}{5}\) × 8 = \(\frac{17}{5}\) × 8 = \(\frac{136}{5}\) = 27 \(\frac{1}{5}\)


| So No | Base | Height | Area of parallelogram |
|---|---|---|---|
| a. | 20 cm | - | 246 \(cm^2\) |
| b. | - | 15 cm | 154.5 \(cm^2\) |
| c. | - | 8.4 cm | 48.72 \(cm^2\) |
| d. | 15.6 cm | - | 16.38 \(cm^2\) |
| Base | Height | Area of triangle |
|---|---|---|
| 15 cm | - | 87 \(cm^2\) |
| - | 31.4 mm | 1256 \(mm^2\) |
| 22 cm | - | 170.5 \(cm^2\) |

Find: (a) \(\frac{1}{2}\) of (i) 2 \(\frac{3}{4}\) (ii) 4 \(\frac{2}{9}\)
(b) \(\frac{5}{8}\) of (i) 3 \(\frac{5}{6}\) (ii) 9 \(\frac{2}{3}\)


| So No | Base | Height | Area of parallelogram |
|---|---|---|---|
| a. | 20 cm | - | 246 \(cm^2\) |
| b. | - | 15 cm | 154.5 \(cm^2\) |
| c. | - | 8.4 cm | 48.72 \(cm^2\) |
| d. | 15.6 cm | - | 16.38 \(cm^2\) |
| Base | Height | Area of triangle |
|---|---|---|
| 15 cm | - | 87 \(cm^2\) |
| - | 31.4 mm | 1256 \(mm^2\) |
| 22 cm | - | 170.5 \(cm^2\) |
